0 个投票

I have an anonymous function, im trying to find each fzero value as variable x in the anonymous function (AC) goes from 0:1:10, how can I do that?
Eq1 = @(A) 2A + A^2 - 5A
Eq2 = @(A) 3A + A^3 - 2A
B=5;
AC = @(A) B - 2 * integral(Eq1,5,A) - x * integral(Eq2,5,A);
j=1;
for x=0:1:10
Z(j)=fzero(AC(x),0)
j=j+1
end

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Stephen23
Stephen23 2020-4-10

0 个投票

You need to parameterize the function:
https://www.mathworks.com/help/matlab/math/parameterizing-functions.html
Note that it is usually simpler and more robust to loop over indices rather than looping over data, e.g.:
Eq1 = @(A) 2*A + A.^2 - 5*A;
Eq2 = @(A) 3*A + A.^3 - 2*A;
B = 5;
AC = @(A,x) B - 2*integral(Eq1,5,A) - x*integral(Eq2,5,A);
X = 0:1:10;
N = numel(X);
Z = nan(0,N);
for k = 1:N
Z(k) = fzero(@(A)AC(A,X(k)),0);
end
Giving:
>> Z
Z =
5.2309 5.033 5.0178 5.0122 5.0092 5.0074 5.0062 5.0054 5.0047 5.0042 5.0038

更多回答（1 个）

darova
darova 2020-4-10

0 个投票

Passing extra parameters
AC = @(A,x) B - 2 * integral(Eq1,5,A) - x * integral(Eq2,5,A);
%%
Z(j) = fzero(@(A)AC(A,x),0)

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