How can I split an array into equal overlapping sub-arrays?
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How can I split an array into equal overlapping sub-arrays?
Simple example where the array divides evenly without any need for overlapping
ArrayX = 1:160;
ArraySplitSize = 4
Result is
1:40, 40:80, 80:120, 120:160
Example where overlapping is needed. I want to keep full size of the array and not cut off anything at the end.
ArrayX = 1:100;
Subarray = 40;
ArraySplitSize = 3;
Result is 1:40, 30:70, 60:100
3 个评论
Image Analyst
2020-4-10
Kelly Kearney
2020-4-10
Also, what's the rule you used to decide which of the overlapping blocks get shorted when the array isn't evenly divisible? E.g. in your latter example, you indicate subarrays of length 40, 41, and 41. Also, in your first example, you listed values with overlaps; I assume that should be 1:40, 41:80, 81:120, and 121:160, right?
mark palmer
2020-4-10
采纳的回答
Walter Roberson
2020-4-10
If you have the Communications Toolbox, the easiest approach is to use buffer() and take the columns of the resulting matrix. buffer() already has logic for overlapping windows built in. Otherwise,
bufflen = length(buffer);
advance = window_size - overlap;
starts = 1 : advance : bufflen;
ends = min(starts + window_size - 1, bufflen);
result = arrayfun(@(S,E) buffer(S:E), starts, ends, 'uniform', 0);
This uses a strictly uniform size. The last few entries might be shorter.
3 个评论
mark palmer
2020-4-10
Walter Roberson
2020-4-10
bufflen = length(ArrayX);
starts = floor(linspace(1, bufflen-Subarray+1, ArraySplitSize));
ends = starts + Subarray - 1;
result = arrayfun(@(S,E) ArrayX(S:E), starts, ends, 'uniform', 0);
mark palmer
2020-4-10
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