Maximum variable size allowed by the program is exceeded.

Question

MD.MASHRAVI SHAMS 2020-4-10

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https://ww2.mathworks.cn/matlabcentral/answers/516899-maximum-variable-size-allowed-by-the-program-is-exceeded

评论： MD.MASHRAVI SHAMS 2020-4-11

采纳的回答： Steven Lord

Hi my code is below

clc

format long g

a=588545.909;

b=10167.688;

c=150;

ox=302;

oy=192;

for oz= 1800:1:2313

oev=a.*ox+b.*oy+c.*oz ;

oce=oev+500000;

less=round(oce.*0.9,3);

x1=250:.001:1550;

y2=150:.001:1450;

z3=1200:.001:2500;

x=perms(x1)

y=perms(x1)

z=perms(x1)

then the error come

Maximum variable size allowed by the program is exceeded for x=perms(x1)

need to overcome the error. How can I?

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Answer 1

Steven Lord 2020-4-10

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https://ww2.mathworks.cn/matlabcentral/answers/516899-maximum-variable-size-allowed-by-the-program-is-exceeded#answer_425221

在 MATLAB Online 中打开

You can't.

The output of perms(x) has factorial(n) rows, where n is the number of elements in x. How big is that?

>> x1=250:.001:1550;
>> vpa(factorial(sym(numel(x1))))
 
ans =
 
1.2633683274814429271576127065521e+7383553

The number of hydrogen atoms in the observable universe is estimated to be around 1e80.

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MD.MASHRAVI SHAMS 2020-4-10

dear Steven,

actually my total code is given below-

clc

format long g

a=588545.909;

b=10167.688;

c=150;

ox=302;

oy=192;

for oz= 1800:1:2313

oev=a.*ox+b.*oy+c.*oz ;

oce=oev+500000;

less=round(oce.*0.9,3);

x=250:.001:1550;

y=150:.001:1450;

z=1200:.001:2500;

o=((a.*x+b.*y+c.*z));

t=o+500000;

v=0.9.*(t);

hvp=((t-less).*100)./t;

hvptrunc=round(hvp,3);

qp=round(t-(t.*(hvptrunc./100)),3);

qpwod= round(t,3);

difwod=round(abs(qpwod-less),3);

dif=round(abs(qp-less),3);

[m,ind]=mink(dif,1);

[mwod,indwod]=mink(difwod,3);

% disp([oz x(ind(1)) y(ind(1)) z(ind(1)) dif(ind(1))]);

T = table(oz,x(ind(1)),y(ind(1)),z(ind(1)),hvptrunc(ind(1)),less,qp(ind(1)),dif(ind(1)))

T1= table(oz,x(indwod(1)),y(indwod(1)),z(indwod(1)),less,qpwod(indwod(1)),dif(indwod(1)))

end

I want to know all the possible combination of the values of x, y and z for whose value will give qp-less= 0.

Steven Lord 2020-4-11

If you multiply both sides of the equation by 1000 (so x, y, and z are integers) you may be able to use some of the techniques for Diophantine equations to obtain your solutions.

MD.MASHRAVI SHAMS 2020-4-11

dear steven, i have write another code for Diophantine equation. but it runs for last 7 hrs

a=588545.909;

b=10167.688;

c=150;

x=250:.001:1550;

y=150:.001:1450;

z=1200:.001:2500;

o=(a.*x+b.*y+c.*z);

t=o+500000==162486009.553;

[xSol, ySol, zsol] = solve(t,[x y z])

is there any wrong in this code?

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Maximum variable size allowed by the program is exceeded.

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