[N,D] = numden(l11);
limit(D,lambda,1,'left')
simplify(expand(limit(N,lambda,1,'left')))
The denominator goes to 0 (but possibly at a different speed than the numerator). We are therefore risking an infinite or nan value.
The numerator goes to 32*2^n .
With n being an integer, 2^n is positive, so -32*2^n is negative, so the numerator is negative.
The limit is therefore positive/zero which would be +infinity
However, really you need to examine the rate at which both parts go to zero. There is a chance that the infinity should be negative. Maple thinks the limit should be signum(-4/0)*infinity which would get you -infinity .
