Putting random values in for loop

Question

SAZZAD HOSSAIN 2012-10-24

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https://ww2.mathworks.cn/matlabcentral/answers/51793-putting-random-values-in-for-loop

Hi everyone

I am writing a program in which i am using the following loop.

for t = 1:1:81; 
    vv(t) = floor(+1*120*sin(2*pi*(t-1)/40)); 
end

The vales of vv are like 0,18,37...... However, i found that my program has some instability due to jumping directly from vv = 0 to vv = 18. Therefore, my intention is to keep the inputs for the loop as it is (otherwise it gets too long to run), but to put few more input values for vv. for example I want to start with 0, 1, 5, 9, 14, 18,37,....... Hence i need to put those 4 values in between 0 and 18 to bring stability into the result. Can anyone please help me.

Thanks in advance

Hossain

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Answer 1

Jonathan Epperl 2012-10-24

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Do what Matt suggested:

VV = floor(+1*120*sin(2*pi*(t-1)/40));

Then add your extra values into VV:

VV = [VV(1) 1 5 9 14 VV(2:end)];

Then run your loop

 for i=1:numel(vv) % presumably 85
      vv = VV(i);
      % your other code
 end

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SAZZAD HOSSAIN 2012-10-24

Thanks Jonathan. Works perfect.

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Answer 2

Matt Kindig 2012-10-24

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Hi Sazzad,

First of all, you don't need the loop: you can just do it like this:

vv = floor(+1*120*sin(2*pi*(t-1)/40));

Second, can you just use a finer resolution of t, such as:

t= 1:0.1:81;
vv = floor(+1*120*sin(2*pi*(t-1)/40));

Now vv changes from 0 to 1 to 3 to 5, etc.

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SAZZAD HOSSAIN 2012-10-24

Hi Matt

Thanks for the answer. The vv = floor (....) part is followed by a lot of other codes and it needs to be in a for loop. And i cannot use finer resolution. the current resolution i am using takes around 2 days to complete so i kind of want to stick to this resolution.

Thanks.

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