find() returns content of {1×0 double} cell array

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chlor thanks 2020-4-15

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/518086-find-returns-content-of-1x0-double-cell-array

评论： chlor thanks 2020-4-17

采纳的回答： darova

在 MATLAB Online 中打开

fullfiles have a list of file paths, RAW has the substrings I like to search for in the file paths.

I want the output AllIndex to be indexes of those found files.

    AllIndex={};
    for k = 1 : length(RAW)
    IndexRAW = strfind(fullfiles, char(RAW(k)));
    Index = find(~(cellfun('isempty', IndexRAW)));
    AllIndex{end+1}=Index
    end

but my output is

AllIndex =
  1×8 cell array
    {1×0 double}    {1×0 double}    {1×0 double}    {1×0 double}    {1×0 double}    {1×0 double}    {1×0 double}    {1×0 double}

its content shown in Editor as

[] [] [] [] [] [] [] []

Please help! Thanks!!

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chlor thanks 2020-4-15

say my fullfiles is = {'\\path\143'} {'\\path\204'} {'\\path\450'}

RAW = {'450'} {'143'}

I want the output AllIndex to be = 3 1

Stephen23 2020-4-15

"Result of strfind is integer arrays but you are trying to use cellfun"

The MATLAB documentation states:

"If str is a cell array of character vectors or a string array, then strfind returns a cell array of vectors of type double."

source: https://www.mathworks.com/help/matlab/ref/strfind.html

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采纳的回答

darova 2020-4-15

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/518086-find-returns-content-of-1x0-double-cell-array#answer_426206

在 MATLAB Online 中打开

What about simple for loops?

ffile = {'\\path\143' '\\path\204' '\\path\450'};
RAW = {'450' '143'};
allind = zeros(size(RAW));
for i = 1:numel(RAW)
    for j = 1:numel(ffile)
        if strfind(ffile{j},RAW{i})
            allind(i) = j;
            break;
        end
    end
end
allind