PI BLOCK IN SIMULINK

101 次查看（过去 30 天）
Uzair Akhtar
Uzair Akhtar 2020-4-15
回答： Animesh 2024-8-22
I have a model in simulink with a PI controller and a transfer function which is shown below.
The PI controller is 3.15(1+2.6s/2.6s) which I have put in ideal form where the proportional(P) is 3.15 and the integral(I) is 2.6 however Im not getting the correct trace on the scope
However when I replace the PI controller with this input output block I have shown below I get the correct answer. Can someone explain what I am doing wrong with the PI block, thanks.
This is what's inside the subsystem input output block.

请先登录，再回答此问题。

回答（1 个）

Animesh
Animesh 2024-8-22
Hi @Uzair Akhtar,
If you look at “PI controller” block’s dialog box, you can see that compensator formula is:
Given the value of “P = 3.15” and “I = 2.6” would generate the compensator as:
But the desired compensator is:
To obtain the above result use, “P = 3.15” and “I = 3.15/2.6”.
Here is an image with correct configurations:
You can refer to the following MathWorks documentation for more information on "PI Controller" block:
https://www.mathworks.com/help/simulink/slref/pidcontroller.html

类别

在 Help Center 和 File Exchange 中查找有关 Aerospace Applications 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by