Replacing values in a logical vector based on a rule

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Amy Hassett
Amy Hassett 2020-4-16
编辑： Stephen23 2020-4-16
So I have a logical column vector, that I have transformed into a double (it is 21080x1). I am now trying to replace every "1" with the corresponding row value from a different array, but what I am getting out is: [0,1].
Any help would be greatly appreciated.
for n= 1:numel(Behaviours) %Behaviours is a 27x1 cell array
temp = strcmp(Group1_KOs.BehaviourType, Behaviours(n)); %creates the logical vector
temp = double(temp); %convert to a double (just in case)
if temp(i) == 1 %where temp(i) is 1, replace with:
temp(i) =Group1_KOs.BehaviourData(i,7); %value in i'th row, 7th column
end

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Stephen23
Stephen23 2020-4-16
编辑：Stephen23 2020-4-16
Try using logical indexing rather than a loop:
idx = strcmp(Group1_KOs.BehaviourType, Behaviours(n));
tmp = double(idx);
tmp(idx) = Group1_KOs.BehaviourData(idx,7)
or alternatively just multiply the index by those values:
tmp = idx.*Group1_KOs.BehaviourData(:,7)

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