how to generate a random array list with fixed sum ?

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tlig zied
tlig zied 2020-4-19
评论： Walter Roberson 2020-4-21
this code distributes fixed number in an array list, for exemple we have sum = 10, and the size of the array list is 3
the code generates this distribution [ 8 1 1] or other distribution...how can I modify this code to obtain a distribution that each value must be between 1 and sum/2 to obtain something like that [3 3 4]
S = 20;
n = 5;
m = 1;
while true
P = ones(S+1,n);
for in = n-1:-1:1
P(:,in) = cumsum(P(:,in+1));
end
R = zeros(m,n);
for im = 1:m
s = S;
for in = 1:n
R(im,in) = sum(P(s+1,in)*rand<=P(1:s,in));
s = s-R(im,in);
end
end
x = find(R<=0);
if x~=0
continue
else
break
end
end
indMaxArry = ceil(n/2);
R = circshift(sort(R),[0,indMaxArry])
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回答（1 个）

Matt J
Matt J 2020-4-20
  2 个评论
tlig zied
tlig zied 2020-4-21
I can't use it because of this constarint n*a <= s <= n*b
Matt J
Matt J 2020-4-21
You haven't told us what any of those symbols mean, but the FEX submission does support bounds on the array elements.

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