Speed up Matrix multiplication
显示 更早的评论
I want to do the following Matrix Multiplication. Problem - Example:
A = rand(3,3,1000000);
B = rand(3,1000000)
How to calculate C faster than with this For-loop? I tried parfor but its only slightly faster.
Furthermore i'd prefer not to install the Parallel Computing Toolbox or MTIMESX. Is it possible just with reshape/permute/bsxfun?
C = zeros(3,1,size(B,2));
for idx=1:size(B,2)
C(:,:,idx) = A(:,:,idx) * B(:,idx);
end
Thanks!
1 个评论
Michael Soskind
2020-4-20
I see a marginal performance improvement by simply getting rid of the middle array index:
A = rand(3,3,1e6);
B = rand(3,1e6);
% original code
tic
C = zeros(3,1,size(B,2));
for idx=1:size(B,2)
C(:,:,idx) = A(:,:,idx) * B(:,idx);
end
toc
% modified code with one fewer array dimension
tic
C = zeros(3,size(B,2));
for idx=1:size(B,2)
C(:,idx) = A(:,:,idx) * B(:,idx);
end
toc
Not sure if that helps or hurts you, but I get about 0.3 sec faster execution time, on average (Goes from 2 sec to 1.7 sec).
Michael
采纳的回答
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Number Theory 的更多信息
产品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!