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column circular permutaion on a matrix

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Abhishek Bakhla
Abhishek Bakhla 2020-4-20
评论： Abhishek Bakhla 2020-4-23
How can I move all the elements of a particular column circulary upwards or circularly downwards by some shift s. I have a matrix A = [ 1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16] and shift columns 1, 2, 3 and 4 by shifts 2, 1 , 3 and 2 respectively then I get the matrix A as A = [9 6 15 12; 13 10 3 16; 1 14 7 4; 5 2 11 8].

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采纳的回答

Ameer Hamza
Ameer Hamza 2020-4-20
Try this
A = [ 1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16];
B = [9 6 15 12; 13 10 3 16; 1 14 7 4; 5 2 11 8];
shift = [2, 1, 3, 2];
C = A; % make a copy
for i=1:numel(shift)
C(:,i) = circshift(C(:,i), -shift(i));
end
Result
>> isequal(B, C)
ans =
logical
1

更多回答（2 个）

Ilian
Ilian 2020-4-20
If you just want to rotate the rows this could work:
s = -3; % shift (both positive and negative values work)
rows = size(A,1);
B = [A(mod(s-rows,rows)+1:end,:); A(1:mod(s-rows,rows),:)];
Stephen23
Stephen23 2020-4-21
No loops:
>> A = [1,2,3,4;5,6,7,8;9,10,11,12;13,14,15,16];
>> S = [2,1,3,2]; % shifts
>> [R,C] = ndgrid(1:4,1:4);
>> B = A(sub2ind([4,4],1+mod(S+R-1,4),C))
B =
9 6 15 12
13 10 3 16
1 14 7 4
5 2 11 8

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