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how to make the matlab code to test the equation below convergent or divergent?

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Muhammad Rohim
Muhammad Rohim 2020-4-21
评论： Ameer Hamza 2020-4-21
below is the matlab code that I used to solve it. but more code is needed to display the convergent or divergent equation above.
function [ Sum_n, series_1 ] = Coba5( n, es )
%Percobaan 3
clc;
clear;
n = input ('nilai signifikan: ');
series_1 = 0
es = 0.5*(10^(2-n));
for ns = 1:100
x = cumsum( sin(2*ns)./ns.^2)
series_1 = series_1 + x
end
disp([es]')
end

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回答（1 个）

Ameer Hamza
Ameer Hamza 2020-4-21
Just find the sum and check if it is convergent or divergent
syms n
term = sin(2*n)/n^2;
y = vpa(symsum(term, n, 1, inf));
if isinf(y)
fprintf('divergent\n');
else
fprintf('convergent\n');
end
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