Sum with a for loop of each 2 elements

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Hi All,

I have been trying to get the sum of each two elements: for example:

I have x=[50 200 20], I need to have the output =[250 220]

50+200

then

200+20

and so on...

clear all; 
clc;
x=[50 200 20];
%x(1:length(x))=x(length(x):-1:1);
for i=1:length(x)-1
    
        c(i) = sum(x); % c(i)=[250 220]
    
end

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Answer 1

Sriram Tadavarty 2020-4-21

编辑：Sriram Tadavarty 2020-4-21

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Hi Ali,

Use the following modification to the code:

clear all; 
clc;
x=[50 200 20];
for i=2:length(x)
    c(i-1) = x(i-1) + x(i);
end

Use can even use movsum function as shown below:

c = movsum(x,2);
c = c(2:end);

Hope this helps.

Regards,

Sriram

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Ali Tawfik 2020-4-21

Hi Sriram,

Thanks for your prompt reply.

actually I do not prefer functions in that situation,

and even when I tried I got the following error

Subscripted assignment dimension mismatch.

So Would you mind helping me to have a command without function ??

thanks,

Sriram Tadavarty 2020-4-21

Sure Ali. Can you once look over the modified answer?

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Sum with a for loop of each 2 elements

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