store variables in a for loop
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Hello,
i m trying to obtain a set of coordinates for this:
function [x, y] = gencircle(xo,yo,r,N)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,N)
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,N)
end
end
for j=1:length(yo)
for i=1:length(xo)
aa=[xout(:,i),yout(:,j)]
end
end
how can i store the vector aa for each loop?
Thanks
采纳的回答
Sriram Tadavarty
2020-4-21
编辑：Sriram Tadavarty
2020-4-21
Hi Davide,
You can make the following modification to the code as shown below, which stores all the loop iteration values in the variable aa:
clear all
xo=[1 2 3 4 5 6 7 8];
yo=[-1 -0.5];
r=0.01;
N=10;
theta=2*pi/N*(1:N+1);
th=0.00235;
for j=1:length(yo)
for i=1:length(xo)
[xout(:,i), yout(:,j)]=gencircle(xo(i),yo(j),r,theta);
[xin(:,i), yin(:,j)]=gencircle(xo(i),yo(j),r-th,theta);
end
end
aa = zeros(size(xout,1),2,length(yo)*length(xo)); % Initialize the variable
tmp = 1;
for j=1:length(yo)
for i=1:length(xo)
aa(:,:,tmp)=[xout(:,i),yout(:,j)];
tmp = tmp+1;
end
end
% aa will be a variable of size length(xout) x 2 x (loop iterations)
% loop iterations here is equal to the product of length(yo) and length(xo) (implies 16)
% Each iteration value can be accessed by indexing from 3rd dimension,
% implies for example fifth iteration can be accessed with aa(:,:,5)
function [x, y] = gencircle(xo,yo,r,theta)
x=(xo+r*cos(theta))';
y=(yo+r*sin(theta))';
end
Hope this helps.
Regards,
Sriram
4 个评论
Stephen23
2020-4-21
It is recommended to preallocate aa before the loops:
Sriram Tadavarty
2020-4-21
Yes. Updated the answer with the variable pre-allocation.
Davide Cerra
2020-4-21
Sriram Tadavarty
2020-4-21
Please do accept the answer, if helped
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