Magnitude and direction from north and east components

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TAPAS
TAPAS 2020-4-22
评论： TAPAS 2020-4-23
I have displacement data components along north and east how to find its magnitude and direction with reference to north(0-360) in matlab. The components may have same sign or opposite both possible.

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Deepak Gupta
Deepak Gupta 2020-4-22
编辑：Deepak Gupta 2020-4-22
Hi Mithun,
You can think of North and East as your X and Y. As you have taken north as reference so use below formulas to calculate magnitude and angle.
Magnitude = sqrt(North^2+East^2);
Theta = atan((-East)/North);
I am using -East because East is 90 degree closewise to North and atan calculates angles in counter clockwise directions from reference.
Thanks,
Deepak
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Deepak Gupta
Deepak Gupta 2020-4-22
Read comments added already and think before asking further questions. Test the code with a known values.

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KSSV
KSSV 2020-4-22
If (x,y) is a componenet
m = sqrt(x^2+y^2) ; % magnitude
theta = atan(y/x) ; % direction

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