a function problem about output number
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Hi guys,
Why I can not get 2 answers for value 1 and 2 the output is only first entriy;
function [num11,num22] = tekcift(num1,num2)
if mod(num1,2)==0
num11=num1^2;
elseif mod(num1,2)==1
num11=num1^3;
else
end
if mod(num2,2)==0
num22=num2^2;
elseif mod(num2,2)==1
num22=num2^3;
else
end
end
回答（1 个）
You need to call the function with two outputs, e.g.:
[N1,N2] = tekcift(... whatever inputs you use...)
Very basic MATLAB concepts, such as how to call functions with multiple output arguments, are explained in the introductory tutorials:
If the function is only intended to work on integer values, then elseif can be replaced with else:
if mod(num1,2)
num11 = num1^3;
else
num11 = num1^2;
end
Or without if:
num11 = num1.^(2+mod(num1,2));
2 个评论
Levent Sakin
2020-4-23
Stephen23
2020-4-23
It works when I call your function:
>> [N1,N2] = tekcift(1,2)
N1 = 1
N2 = 4
Unfortunately my magic crystal ball is at the workshop today getting fixed, so we will have to rely on you actually showing me exactly how you are calling the function.
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2020-4-23
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