How to convert an image to binary matrix

2020 4 25
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更新时间：2021 9 29
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I have an image P with dimension MxN. How to convert into dimension Mx8N ?
I have used P1 = dec2bin(P);
I am getting 65336x8 but I want 256x2048 how to do so ?

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Walter Roberson
Walter Roberson 2020-4-25

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P1 = reshape( permute(reshape( (dec2bin(P, 8) - '0').', 8, size(P,1), size(P,2)), [2 1 3]), size(P,1), size(P,2)*8);
This preserves rows and expands each column to 8 columns -- so like
P(1,1)bit1 P(1,1)bit2 P(1,1)bit3 P(1,1)bit4 P(1,1)bit5 P(1,1)bit6 P(1,1)bit7 P(1,1)bit8 P(1,2)bit1 P(1,2)bit2 and so on
Another approach would be:
P1 = reshape( cat(3, bitget(P,8), bitget(P,7), bitget(P,6), bitget(P,5), bitget(P,4), bitget(P,3), bitget(P,2), bitget(P,1)), size(P,1), size(P,2)*8);
This preserves rows, and places all of the most significant bits together, then the second most significant, then the third most, and so on,
P(1,1)bit1 P(1,2)bit1 P(1,3)bit1 ... P(1,256)bit1 P(1,1)bit2 P(1,2)bit2 .. P(1,256)bit2 P(1,1)bit3 P(1,2)bit3 and so on

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KALYAN ACHARJYA
KALYAN ACHARJYA 2020-4-25
编辑：KALYAN ACHARJYA 2020-4-25

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>> ima=magic(3) % Lets suppose ima is a Image
ima =
8 1 6
3 5 7
4 9 2
>> result=dec2bin(ima,8)
result =
9×8 char array
'00001000'
'00000011'
'00000100'
'00000001'
'00000101'
'00001001'
'00000110'
'00000111'
'00000010'
>> data2=cellstr(result)
data2 =
9×1 cell array
'00001000'
'00000011'
'00000100'
'00000001'
'00000101'
'00001001'
'00000110'
'00000111'
'00000010'
>> result3=reshape(data2,[3,3])
result3 =
3×3 cell array
'00001000' '00000001' '00000110'
'00000011' '00000101' '00000111'
'00000100' '00001001' '00000010'
#If you further go for cell to array, then '00000010' represents as 10 only, hence I showed with cell array

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