plotting graphs in matlab
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Hello
If i had the following
clear
clc
x=0:10
y=-2*x+6
y1=3*x
plot(x,y)
hold on
plot(x,y1)
how would i just plot the graph with the limits being the x and y intercept
7 个评论
Geoff Hayes
2020-4-25
Elliot - plaese clarify what you mean by with the limits being the x and y intercept. What do you want the minimum and maximum limits for the x and y axes?
Elliott Cameron
2020-4-25
Star Strider
2020-4-25
Note that ‘y1’ intercepts both the x and y axes at (0,0).
Elliott Cameron
2020-4-25
Tommy
2020-4-25
You can solve for the intercepts using the equation for y1 and update the axes limits accordingly:
clear
clc
x=0:10;
y1=-2*x+6;
y=3*x;
plot(x,y)
hold on
plot(x,y1)
yint = 6; % -2*0 + 6 => 6
xint = 3; % (0 - 6)/(-2) => 3
ax = gca;
ax.XLim(2) = xint;
ax.YLim(2) = yint;
dpb
2020-4-25
@Tommy...you have/are developing my habit of putting Answers in Comments... :)
Tommy
2020-4-25
Ah! Yes I agree... I do often question if I really understand what's being asked, and whether my "answer" is a full answer, but too often I default to the comment section
采纳的回答
Tommy
2020-4-25
You can solve for the intercepts using the equation for y1 and update the axes limits accordingly:
clear
clc
x=0:10;
y1=-2*x+6;
y=3*x;
plot(x,y)
hold on
plot(x,y1)
yint = 6; % -2*0 + 6 => 6
xint = 3; % (0 - 6)/(-2) => 3
ax = gca;
ax.XLim(2) = xint;
ax.YLim(2) = yint;
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