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Is there something like 'array colon'? in other words how can I apply colon operator to all the elements of an array (please read the text below so my question will make sense)?

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Farzaneh
Farzaneh 2012-10-28
A = [1 10 16 23];
A-3:A+2 will result in [-2,-1,0,1,2,3]; In other words colon operates only on the first element of array A. However I want to apply A-3:A+2 on all the elements of A; I know I can get this by a loop, like :
u=[];for i=1:4, u=[u,A(i)-3:A(i)+2]; end
However I wonder if there is a way to do this without using loop. (The actual array I am working with is too long to loop through it.)
This sounds like a super simple question but I have no ides how to do it in a simple way (other than looping).
I so much appreciate any help.

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采纳的回答

Matt Fig
Matt Fig 2012-10-28
A = [1 10 16 23];
u = reshape(bsxfun(@plus,A,(-3:2).'),1,[])

更多回答（3 个）

Azzi Abdelmalek
Azzi Abdelmalek 2012-10-28
编辑：Azzi Abdelmalek 2012-10-28
do you mean a division
A = [1 10 15 23];
(A-3)./(A+2 )
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Jan
Jan 2012-10-28
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Farzaneh
Farzaneh 2012-10-28
When I use mcolon , it gives me this error:
Undefined function 'getclassidmex' for input arguments of type 'double'.
Error in castarrays (line 16) id = getclassidmex(varargout{:}); % get id from 1-12, ordered like numclass
Error in mcolon (line 50) [i1,d,i2] = castarrays(i1(:),d(:),i2(:));
Matt Fig
Matt Fig 2012-10-28
MCOLON is a mex function that must be compiled. You don't need MCOLON to do what you want to do here anyway. See my solution.

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Chris A
Chris A 2012-10-28
编辑：Chris A 2012-10-28
Here is one way to do this:
A = [1 10 16 23];
res=reshape(repmat((-3:2)',1,numel(A))+repmat(A,6,1),[],1);

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