Taking data from loops and the plotting them outside the loop

Question

Austin Hernandez 2020-4-27

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/520989-taking-data-from-loops-and-the-plotting-them-outside-the-loop

编辑： Mehmed Saad 2020-4-27

I need to plot a graph based upon the answers given (there's a prompt window before this).

In my for loop, I have an if, elseif, and else statement, which gives 3 very different values. Should I try to put all these into 1 cell array? How can I access the data of each array and then plot it?

Or, if I do this step (make a matrix and not an array) and construct a matrix for each of the 3 options. So if it were like:

h = 0:1:10
y = zeros(size(h));
v = zeros(size(h));
o = zeros(size(h));
prompts = {'enter 1'};
dlg = 'title';
hold on
for i=1:5
    A = inputdlg(prompts, dlg);
    Aa = str2double(A);
    x = Aa(1);
    if x == 1
        y(i,:) = 1000*h;
        m = m + 1;
        plot(h,y(i,:));
    elseif x == 0
        v(i,:) = h+1;
        u = u + 1;    
        plot(h,v(i,:));
    else 
        o(i,:) = -h*5;
        c = c + 1; 
        plot(h,o(i,:));
    end
end
end

This will give 3 different matrices of the 3 different types of answers. When I used this option, this method will generate a new row in the matrix of each output. So if I'm on loop 5, and the if statement is triggered, and I triggered the same statement in the very first loop, then I'll get a matrix like:

v =
   2     3     4     5     6     7     8     9    10    11
   0     0     0     0     0     0     0     0     0     0
   0     0     0     0     0     0     0     0     0     0
   0     0     0     0     0     0     0     0     0     0
   2     3     4     5     6     7     8     9    10    11

How can I take the data from the rows that have nonzeros and then plot them with different boundaries on the x-axis?

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Answer 1

Mehmed Saad 2020-4-27

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/520989-taking-data-from-loops-and-the-plotting-them-outside-the-loop#answer_428592

在 MATLAB Online 中打开

Initialize these variables

m=1;u=1;c=1;

replace i with m,u and c in their cases

    if x == 1
        y(m,:) = 1000*h;
        plot(h,y(m,:));
        m = m + 1;
    elseif x == 0
        v(u,:) = h+1;
        plot(h,v(u,:));
        u = u + 1;
    else 
        o(c,:) = -h*5;
        plot(h,o(c,:));
        c = c + 1;
    end

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Austin Hernandez 2020-4-27

Ah, thank you! So the counter of m = m + 1 is necessary to capture each entry to the loop?

Mehmed Saad 2020-4-27

编辑：Mehmed Saad 2020-4-27

在 MATLAB Online 中打开

There's another way but it is computationaly costly and not recommended

h = 0:1:10
y=[];v=y;o=[];
prompts = {'enter 1'};
dlg = 'title';
hold on
for i=1:5
    A = inputdlg(prompts, dlg);
    Aa = str2double(A);
    x = Aa(1);
    if x == 1
        y = [y;1000*h];
        plot(h,y(end,:));       
    elseif x == 0
        v = [v;h+1];
        plot(h,v(end,:));
    else 
        o = [o;-h*5];
        plot(h,o(end,:));
    end
end