How can I convert datetime vector to datenum (class-double)

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Farshid Daryabor 2020-4-28

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回答： Peter Perkins 2020-4-30

example.mat

Please find attached file, time vector is original format in double I have, for some reason (preprocessing analysis) I have converted it to datetime format (Time) using below command. Again I want to convert Time to the original format (ie, class-double) according to the Pivot Year (1950-01-01). I really appreciate if someone can help me.

Time = datetime (time * 60 * 60 * 24, 'ConvertFrom', 'epochtime', 'Epoch', '1950-01-01');

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Farshid Daryabor 2020-4-28

I tried this one, but cannot be exactly same original one. You can test it by converting "iwant" using below commend to datetime is not what I expect.

Time = datetime(iwant*60*60*24,'ConvertFrom','epochtime','Epoch','1950-01-01');

see form and year

Farshid Daryabor 2020-4-28

Dear Ameer,

Thanks very good

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Answer 1

Ameer Hamza 2020-4-28

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在 MATLAB Online 中打开

try this

pvtYear = datetime(1950, 01, 01);
time_ = datenum(Time-pvtYear); % time_ is same as time, minor differences probably due to floating point errors

Result:

>> all(ismembertol(time_,time))
ans =
  logical
   1

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Farshid Daryabor 2020-4-28

Thanks Ameer, very good

Ameer Hamza 2020-4-28

Glad to be of help.

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Answer 2

Peter Perkins 2020-4-30

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You almost certainly DO NOT want to convert datetimes to datenums. In recent versions of MATLAB, there are not many good reasons to want to use datenum at all.

If you mean, "I need to convert back to elapsed time since 1950", that's maybe a different story, but those are not "datenums". Here's a simple way to do it:

dt = days(myDatetimes - datetime(1950,1,1))

However, if your values are counting days since 1950, you are shooting yourself in the foot -- you will never have an exact representation of time within day because 1/24, 1/1440. 1/86400, none of them are representable exactly in double precision.

Unless your timestamps are always at 00:00:00, 03:00:00, etc., you would be much better off using seconds.