Why does a Boolean XOR block become a bitwise operation in generated C code?
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When I generate code from a Boolean XOR block, it becomes a bitwise operation in the generated C code. Why is this the case, and are there any workarounds?
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MathWorks Support Team
2024-10-18
编辑：MathWorks Support Team
2021-10-14
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The "^" operator that is produced as generated code for the Logical XOR block is expected behavior since there is no true Boolean XOR operator in C.
If you wish to generate the relation operator "!=" instead, in the place of the Logical Operator XOR block you can use the Relational Operator block and select "~=".
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