How can I plot a horizontal line for a polar plot?
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I have a polar plot of two lines with an equation to get the percent error between them. How do I plot a horzontal line where the percent error is at 5%?
Code is below.
Thanks in advance.
alpha = 0:0.01:(1/2) * pi;
y = sin(alpha);
polarplot(alpha,y) %first plot
pause(1)
hold on
polarplot(y.*(alpha)==alpha) %second plot
pError = 100*(alpha-sin(alpha))./sin(alpha); %percent difference
disp(pError);
pause(1)
polarplot(pError .* .05) %horizontal line at 5% error
hold off
2 个评论
Star Strider
2020-4-29
It looks as though you already did that:
polarplot(pError .* .05) %horizontal line at 5% error
What do you want it to be?
Christian Bellew
2020-4-29
采纳的回答
Star Strider
2020-4-29
This plots the horizontal line:
polarplot(acos(pError)./asin(pError) * 0.05/max(pError), 'LineWidth',1) %horizontal line at 5% error
I am not sure how to scale it to be certain it meets the 5% criterion, since I am not certain what you are doing.
Another option:
polarplot(acos(pError-2*pi)./asin(pError-2*pi) * 0.05/max(pError), 'LineWidth',2) %horizontal line at 5% error
I defer to you for the proper scaling.
.
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