Simple Iterative expression needed solved

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James Paltani
James Paltani 2020-4-30
评论： Walter Roberson 2020-4-30
Assuming w is an integer (w = 1, 2, 3, …), write an iterative calculation to determine the minimum w value that will bring the result of the following expression to greater than 10,000. Display this minimum w value and the corresponding result of the expression.

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回答（2 个）

Walter Roberson
Walter Roberson 2020-4-30
initialize. while the condition is not met, increment.
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James Paltani
James Paltani 2020-4-30
编辑：James Paltani 2020-4-30
This is what i have so far.. it says illegal "greater than" operator. What should i differently
clc,clear
syms w
e = sqrt((10*w^2)-4*w+2);
for e > 10000,
solve(w)
Walter Roberson
Walter Roberson 2020-4-30
syms w
e = sqrt((10*w^2)-4*w+2);
w = ceil(max(double(solve(e==10000))));
But this does not use a loop like you are required to do. You should not be using symbolic toolbox for this problem.
You should be initializing w to the lowest value of the range. Then you calculate e based on that w. Test whether it has reached the necessary value yet. If it has not, increment w and recalculate e and loop back.

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Mrutyunjaya Hiremath
w = 1; y = 0;
while(y < 10000)
% your equation
y = sqrt(10*w*w - 4*w + 2);
w = w + 1;
end
disp(w)
disp(y)

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