Fibonacci sequence with loop

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Lisa Fontana
Lisa Fontana 2020-5-1
回答： Tanuj Monu 2022-1-23
I need help with these exercise:
Write a function Fibonacci(n) that takes n as an
input and produces the corresponding Fn as an output
• Use a for loop that computes the first 10 numbers (1<= n <= 10)
• Use a while loop that computes all Fibonacci numbers below 1000 (All n that Fn<1000).
If you can also add explanations it will be perfect
  2 个评论
James Tursa
James Tursa 2020-5-1
What have you done so far? What specific problems are you having with your code?
Lisa Fontana
Lisa Fontana 2020-5-1
I haven't actually done anything, I don't know how to write the function with for and while loop..

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采纳的回答

Prasad Reddy
Prasad Reddy 2020-5-1
clc
clear all
Fibonacci(1000)
function fibn=Fibonacci(n)
fibn=[1 1];
i=3;
while fibn(i-1)<n
fibn(i)=fibn(i-2)+fibn(i-1);
i=i+1;
end
fibn=fibn(1:end-1);
end
% This is code in While loop. please try to understand it. if dont understand please leave a comment.
% Please give a up thumb if this code works. thank you in advance.

更多回答（2 个）

Prasad Reddy
Prasad Reddy 2020-5-1
clc
clear all
Fibonacci(10)
function fibn=Fibonacci(n) % we are defining a function Fibonacci
fibn=[1 1] % initialiing first two values for fibonacci series
for i=3:n % since already two values are present we are starting the loop from third element
fibn(i)=fibn(i-2)+fibn(i-1); % i th element in fibnochi series is the sum of previous two elements
end
end
  8 个评论
显示 6更早的评论
Prasad Reddy
Prasad Reddy 2020-5-1
编辑：Prasad Reddy 2020-5-1
@ Lisa Fontana Ok madam i can understand. post any questions which you dont understand, we are ready to help. It seams that this is your firt question in this community. happy learning.
Lisa Fontana
Lisa Fontana 2020-5-1
Yes this is my first question! The lab that will host me sent me some slides with exercises but they're not complete; at the beginning the exercises were intuitive but now they are getting complex. thanks for the help and availability, good evening

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Tanuj Monu
Tanuj Monu 2022-1-23
function f = fib(n)
f(1) = 1;
f(2) = 1;
for i = 3:n
f(i) = f(i-1) + f(i-2);
end
f = f(end);
end

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