Symbolic integration using 'int': Find integration constant using symbolic initial condition

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Roi Roded
Roi Roded 2020-5-2
回答： Walter Roberson 2020-5-2
Hi, using 'syms' and 'int' I solve symbolic integral, which provides me the answer with integration constant 'C'. The result is a long-expression and I wish to define the initial condition, e.g., y(0)=a, so I can find the closed-form expression with the integration constant.
Is there a way to define symbolic initial conditions and get the complete solution?
best,

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Walter Roberson
Walter Roberson 2020-5-2
constant = a - subs(TheExpression,Variable,0) + C
For example, TheExpression(0) might be 5+C and a might be 2, and 2 - (5+C) + C = 2-5 = -3 which is the constant of integration

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