HOW TO STRİNG TO CHAR
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how do I print this expression''110 011101110001111001111010 1111000001000100011011000111010'' in a matrix of 10x10?
采纳的回答
Image Analyst
2020-5-2
You can't. It's only 58 characters long - 60 if you include the spaces:
expression = "1100111011100011110011110101111000001000100011011000111010"
length(expression)
length(char(expression))
expression =
"1100111011100011110011110101111000001000100011011000111010"
ans =
1
ans =
58
In the meantime, try
expression = "1100111011100011110011110101111000001000100011011000111010"
length(expression)
charVector = char(expression)
length(charVector)
charMatrix = reshape(charVector, 2, 29) % or 10 by 10
4 个评论
Gökhan BAYKARA
2020-5-2
Image Analyst
2020-5-2
expression = "11 0011101110001111001111010 111100000 1000100011011000 11101011 001111010111 1000001000 1000110110 00111010"
% Get rid of spaces
expression = erase(expression, ' ')
% Change from string to character vector.
charVector = char(expression) % 100 characters long now
charMatrix = reshape(charVector, 10, 10)
expression =
"11 0011101110001111001111010 111100000 1000100011011000 11101011 001111010111 1000001000 1000110110 00111010"
expression =
"1100111011100011110011110101111000001000100011011000111010110011110101111000001000100011011000111010"
charVector =
'1100111011100011110011110101111000001000100011011000111010110011110101111000001000100011011000111010'
charMatrix =
10×10 char array
'1111100101'
'1010000100'
'0010011110'
'0010011000'
'1100111001'
'1110101001'
'1101010011'
'0110101010'
'1010110101'
'1010011010'
Gökhan BAYKARA
2020-5-2
n your result vector, your value of 1 for the name length and 10 for the number will be fixed and will not change. But everyone's name is different because it is long; BINARY will be stored in the 5-bit data of the vector since SAHIN in the sample name has 5 values The total length in the format will be 5x (1 + 5 + 10) = 80 characters. Occupation in total, considering your name to be up to 9 characters Since the number of characters you can get is 5 * (1 + 9 + 10) = 100, in the 10x10 matrix, 0 * for your 0 values in your result vector, 1 You can create your QR code to print '' (space) for its values. NOTE: Since 80 characters are occupied for the name given in the example, the remaining places in the matrix are blank "*" will be printed. QR code for the sample given:
Image Analyst
2020-5-2
Is this homework? Because it looks like it and we don't want you to get into trouble by submitting my answer as your own. Please read this link.
更多回答（1 个）
Gökhan BAYKARA
2020-5-2
0 个投票
n your result vector, your value of 1 for the name length and 10 for the number will be fixed and will not change. But everyone's name is different because it is long; BINARY will be stored in the 5-bit data of the vector since SAHIN in the sample name has 5 values The total length in the format will be 5x (1 + 5 + 10) = 80 characters. Occupation in total, considering your name to be up to 9 characters Since the number of characters you can get is 5 * (1 + 9 + 10) = 100, in the 10x10 matrix, 0 * for your 0 values in your result vector, 1 You can create your QR code to print '' (space) for its values. NOTE: Since 80 characters are occupied for the name given in the example, the remaining places in the matrix are blank "*" will be printed. QR code for the sample given:
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