where is the error? lagrange

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Dasom Kim
Dasom Kim 2020-5-3
编辑： Ameer Hamza 2020-5-3
when i execute this code, error comes in y^lag;
how can i fix it?
function approx = lagrange(x,y,x_bar)
n = length(x);
for i = 1:n
value = ones(1,length(x_bar));
for k = 1 : n
if k ~= i
value = value.^(x_bar-x(k))/(x(i)-x(k));
end
end
lag (i,:) = value ;
end
approx = y^lag;
end

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回答（1 个）

Ameer Hamza
Ameer Hamza 2020-5-3
编辑：Ameer Hamza 2020-5-3
Use element-wise exponential operator
approx = y.^lag;

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