i got an error when i run this code ? Error using plot
显示 更早的评论
R=2;
meo=5;
ru=0:1:30*1;
syms k
Pout_k1=((2^(2*R)-1)^k).*symprod(1./(ru*5),k,1,1);
Pout_k2=((2^(2*R)-1)^k).*symprod(1./(ru*5),k,1,2);
Pout_k5=((2^(2*R)-1)^k).*symprod(1./(ru*5),k,1,5);
plot(ru,Pout_k1,ru,Pout_k2,ru,Pout_k5)
6 个评论
Ameer Hamza
2020-5-3
What is the value of 'k' in ((2^(2*R)-1)^k) on the line
((2^(2*R)-1)^k).*symprod(1./(ru*5),k,1,1);
Osama Dwairi
2020-5-3
Ameer Hamza
2020-5-3
Then what are you trying to do here: symprod(1./(ru*5),k,1,1)? Can you attach the image of the equations in mathematical form?
Osama Dwairi
2020-5-3
Ameer Hamza
2020-5-3
编辑：Ameer Hamza
2020-5-3
Yes, that is obvious from symprod. But what are its limits? and what is its index variable? You can attach the image in the comment.
Osama Dwairi
2020-5-3
the limit is i from 1 to k
i want to plot this function for k=1 ,k=2 ,k=5
note : gama is variable eqal ru*5
R=2
回答（1 个）
Ameer Hamza
2020-5-3
编辑：Ameer Hamza
2020-5-3
Try this code, without symbolic variables.
R=2;
meo=5;
ru=1:30;
Pout = @(k) ((2^(2*R)-1)^k).*prod(1./(ru(1:k)*5));
Pout_k1 = Pout(1);
Pout_k2 = Pout(2);
Pout_k3 = Pout(5);
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2020-5-3
2020-5-3
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