solve command returns sym instead of numerical answer

2012 10 30
2 个回答
9 次查看（30 天）

1 个投票

The code below is intended to return values for T for any number N and creates a a system of equations to do so.
clear
clc
n=input('enter n value :');
T=sym('T', [n 1]);
for x=1:n
if x==1
eqmatrix(x)=(0==2*T(x+1)-(2+1/(n^2))*T(x)+1/(4*n^2));
elseif 1<x && x<n
eqmatrix(x)=(0==T(x+1)+T(x-1)-(2+(1/(n^2)))*T(x)+1/(4*n^2));
elseif x==n
eqmatrix(x)=(0==2*T(x-1)-(2+1/(n^2))*T(x)+1/(4*n^2));
end
end
solve(eqmatrix)
This program returns a sym matrix instead of the numerical answers I was hoping for. What am I doing wrong?
enter n value :5
ans =
T1: [1x1 sym]
T2: [1x1 sym]
T3: [1x1 sym]
T4: [1x1 sym]
T5: [1x1 sym]

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回答（2 个）

Walter Roberson
Walter Roberson 2012-10-30

1 个投票

solve() always returns symbolic answers, even if the results have no symbols in them. You may wish to use double() to convert to double precision values.
Star Strider
Star Strider 2012-10-30
编辑：Star Strider 2012-10-30

1 个投票

It gives numeric answers. You simply aren't asking it to display them.
Ts = solve(eqmatrix)
then, since Ts is a structure, use:
Tn = structfun(@double,Ts)
to produce their double equivalents:
Tn =
250.0000e-003
250.0000e-003
250.0000e-003
250.0000e-003
250.0000e-003

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Jon B
Jon B
2012-10-30

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