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Hi, I have a matrix A with size 32*32 and I need to study the similarity between all pixels.
The similairty between a pixel Xi and another pixel Xj in the neighbourhood of Xi is detemine by an exponantially decaying fuction of the squared difference in thier intensity values:
Sij = exp (-a (I(Xi) - I(Xj))^2);
% where a is a scale (a = 30) and I(x) is denotes the intensity of pixel x .
I need to study the similarity between pixel in location (1,1) with the ather pixels and recored the values of simialrity in matrix A1, so matrix A1 will has a size 32*32.
the value of A1(1,1) is the similarity between pixel A(1,1) with pixel A(1,1) ,
the value of A1(1,2) is the similarity bwtween pixel A(1,1) with pixel A(1,2) ,
and so on.
Thanks ♥

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David Hill
David Hill 2020-5-6

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a=.1;
B=exp(-a*(A-A(1,1)).^2);%comparing all pixels to A(1,1)

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Thank you so much ♥
David, how can I use for loop to compare all pixels togathers?
so I will get 32*32 similarity matrix.
David Hill
David Hill 2020-5-6
Not sure what you mean. In the above example, B is a 32x32 matrix that compares all pixels to A(1,1).
We compared pixel A(1,1) with all pixels and recoreded the result in B matrix.
Now, I need to compare pixels A(1,2) with all pixels and recored the result in matrix B1
and compare pixels A(1,3) with all pixels and recored the result in matrix B2
.
.
and up to compare pixels A(32,32) with all pixels and recored the result in matrix B1023
so, I will get 32*32 = 1024 similarity matrix.
did you understand what I mean?

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