Problem 44951. Verify Law of Large Numbers
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function dice_diff = loln(N)
add = 0; mean = 0; mean1 = 0;add1=0;
for c=1:1*exp(8)
num = randi(N);
add = add + num;
end
mean = add/(1*exp(8))
for c=1:N
add1=add1+c;
end
mean1=add1/N
dice_diff = mean-mean1
end
The code works fine but the result is not as expected. Could anyone tell the reason?
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Walter Roberson
2020-5-7
If you want 2980 iterations then why not use 2980 instead of exp(8) ?
mean = add/(1*exp(8))
Incorrect. You do an integer number of iterations, 2980, but you divide by exp(8) which is about 2980.96 so you get the wrong mean() value. You sould be dividing by the number of iterations you do. Or you should use mean()
5 个评论
Walter Roberson
2020-5-7
The question requires that you simulate 1e8 rolls, not 1*exp(8) . 1e8 is 1*10^8
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