3D matrix generic loop calculation
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Dear sir/ma'am
I have a 3D matrix as
y(:,:1)=h(:,:,1)*x(:,:,1)+h(:,:,2)*x(:,:,2)+h(:,:,3)*x(:,:,3)+h(:,:,4)*x(:,:,4)
y(:,:2)=h(:,:,5)*x(:,:,1)+h(:,:,6)*x(:,:,2)+h(:,:,7)*x(:,:,3)+h(:,:,8)*x(:,:,4)
y(:,:3)=h(:,:,9)*x(:,:,1)+h(:,:,10)*x(:,:,2)+h(:,:,11)*x(:,:,3)+h(:,:,12)*x(:,:,4)
y(:,:1)=h(:,:,13)*x(:,:,1)+h(:,:,14)*x(:,:,2)+h(:,:,15)*x(:,:,3)+h(:,:,16)*x(:,:,4)
But I want to compute generic matlab code as a loop for this implementation such that I can operate any value of h,x,y matrix and reach the same result as above description.
Thank you.
采纳的回答
Ameer Hamza
2020-5-9
编辑：Ameer Hamza
2020-5-14
Something like this
h = rand(5, 5, 16);
x = rand(5, 5, 4);
y = zeros(size(x));
count = 1;
for i=1:size(x, 3)
for j=1:4
y(:,:,i) = y(:,:,i) + h(:,:,count)*x(:,:,j);
count = count + 1;
end
end
7 个评论
anindita Roy
2020-5-11
Ameer Hamza
2020-5-11
Oh! I missed the addition in my original code. Check the updated code. Now you can see the addition too.
anindita Roy
2020-5-11
Ameer Hamza
2020-5-11
I am glad to be of help.
anindita Roy
2020-5-14
Ameer Hamza
2020-5-14
You are correct. I missed that. The 'j' should appear in the indexing of 'x'. Check the updated code.
anindita Roy
2020-5-18
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