Multiply values by the number of days in each month

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BN
BN 2020-5-11
回答： Star Strider 2020-5-12
Dear all,
I have a 41x35x360 array namely C. So the C has 360 pages; while 360 represents months from 1-1-1989 (to 12-31-2018 which is 360 months). I want to multiply the value inside each page to the number of days in each month (considering leap and non-leap years). If it is matter 41 and 35 are latitude and longitude, respectively.
C = rand(41,35,360) ; % random 3d data
For example:
C(41, 35, 1) * number of days in January 1989
C(41, 35, 2) * number of days in February 1989
...
C(41, 35, 360) * number of days in December 2018
Thank you

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采纳的回答

Star Strider
Star Strider 2020-5-12
Use the eomday function to find the number of days in each month:
yearv = 1989:2018;
for k = 1:numel(yearv)
daysInMonth(k,:) = [yearv(k), eomday(yearv(k), 1:12)];
end
This creates a matrix where the first column is the year and columns 2:13 are the days in each month of that year.
Adapt it to provide the information you need for your array.

更多回答（1 个）

the cyclist
the cyclist 2020-5-12
C = rand(41,35,360) ; % random 3d data
daysNonLeap = [31; 28; 31; 30; 31; 30; 31; 31; 30; 31; 30; 31];
daysLeap = daysNonLeap;
daysLeap(2) = 29;
daysFourYear = [daysNonLeap; daysNonLeap; daysNonLeap; daysLeap];
daysThirtyYear = [repmat(daysFourYear,7,1); daysNonLeap; daysNonLeap];
C = C .* permute(daysThirtyYear,[3 2 1]);

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