Specifying a range in a double
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% Values is a 401x1 double: 1 - 401
% In this example, I want to take the mean from Values(90) to Values(110).
% Specify Bounds
MAX = 90; %
MIN = 110;
idy = find(Values == MIN);
idz = find(Values == MAX);
Values = mean(Values(idy:idz));
This is simple & should be returning 1 number from Values after taking the mean, but it's resulting in a 1x7^6 double.
Is there a syntax error that I'm overlooking here?
1 个评论
Fangjun Jiang
2020-5-15
code is simple enough. run the code line by line and see where is wrong.
The numerical value for MAX and MIN seems to be reversed. Is that correct?
采纳的回答
William Alberg
2020-5-15
I think, that you want to do this:
MAX = 110;
MIN = 90;
id = find( (MIN <= Values) & (Values <= MAX) )
Values = mean(Values(id))
I switched the MIN/MAX values
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