# Specifying a range in a double

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Keith Grey2020-5-15

% Values is a 401x1 double: 1 - 401
% In this example, I want to take the mean from Values(90) to Values(110).
% Specify Bounds
MAX = 90; %
MIN = 110;
idy = find(Values == MIN);
idz = find(Values == MAX);
Values = mean(Values(idy:idz));
This is simple & should be returning 1 number from Values after taking the mean, but it's resulting in a 1x7^6 double.
Is there a syntax error that I'm overlooking here?
##### 1 个评论显示隐藏 无
Fangjun Jiang 2020-5-15
code is simple enough. run the code line by line and see where is wrong.
The numerical value for MAX and MIN seems to be reversed. Is that correct?

### 采纳的回答

William Alberg 2020-5-15
I think, that you want to do this:
MAX = 110;
MIN = 90;
id = find( (MIN <= Values) & (Values <= MAX) )
Values = mean(Values(id))
I switched the MIN/MAX values
##### 1 个评论显示隐藏 无
Keith Grey 2020-5-15
Ah, I see what I did now! The MAX value was lower than the MIN, so of course the computer's going to hate that. Thank you very much!

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