solving quartic eqn returns root
显示 更早的评论
When I solve a quartic equation using solve by following the following steps
syms H Bo
eqn=H^4 + Bo/15*H^3 + 24/15*H + 4/15*Bo==0;
solx=solve(eqn,H)
I get no explicit functional expression for H in terms of Bo but the following result:
solx =
root(z^4 + (Bo*z^3)/15 + (8*z)/5 + (4*Bo)/15, z, 1)
root(z^4 + (Bo*z^3)/15 + (8*z)/5 + (4*Bo)/15, z, 2)
root(z^4 + (Bo*z^3)/15 + (8*z)/5 + (4*Bo)/15, z, 3)
root(z^4 + (Bo*z^3)/15 + (8*z)/5 + (4*Bo)/15, z, 4)
How do I get solve the above quartic equation and get an explicit expression for H in terms of Bo?
采纳的回答
更多回答(0 个)
类别
在 帮助中心 和 File Exchange 中查找有关 Symbolic Math Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!