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c++ problem with the following code can't display the odds num

1 次查看(过去 30 天)
#include<stdio.h>
// main function
int main(void){
// declare strings
int nums[11] = {1,2,3,4,5,6,7,8,9,10,11};
char odds[20], evens[20];
// setup indexes to track current index of arrays.
int odd_index, even_index, num_index, remainder, i;
char curr_num;
num_index=0;
odd_index=0;
even_index=0;
remainder=0;
for(i = 1; i < 10; i++){
curr_num = nums[i];
remainder = curr_num %2;
if (remainder == 0) {
evens[even_index] = curr_num;
even_index++;
}else{
odds[odd_index] = curr_num;
odd_index++;
}
}
printf("%s is the odd nums \n", odds);
return 0;
}

回答(1 个)

Walter Roberson
Walter Roberson 2020-5-16
编辑:Walter Roberson 2020-5-16
To be able to display output in a C function called from MATLAB, you need to use https://www.mathworks.com/help/matlab/apiref/mexprintf.html mexPrintf() instead of printf()
You will also need to build the interface properly in order to call the code from MATLAB; see https://www.mathworks.com/help/matlab/call-mex-files-1.html
Also, since you are building a character vector, you should be careful to store printable characters in it. You are storing the binary value of the integers such as 3 into the odds array, where it will become char(3) rather than '3' . And remember your numbers go up to 11, so if you want printable characters you need two characters for 10 and 11. And remember a seperator between the characters.
  1 个评论
James Tursa
James Tursa 2020-5-18
And the strings are not null-terminated, so the printf can run off the end of the array into invalid memory.

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