Creating a data matrix that self generates.

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I want to create a 10x10 matrix using 0(x99) & 1(x1) that will randomly regenerate 'n' times. I also want to count when 1 changes position within the matrix.

For example:

Original: 1st Gen: 2nd Gen:

1 0 0 0 0 0 0 0 0 0 0 0 0 0 1

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

0 0 0 0 0 0 0 0 1 0 0 0 0 0 0

0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

Counter = 0 Counter = 1 Counter = 2

Can anyone think of a way to do this?

Thanks,

Joe

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Answer 1

Stijn Haenen 2020-5-18

在 MATLAB Online 中打开

1 个投票

somthing like this:

count=0;
m=zeros(100,1);
rand_int=datasample(1:100,1);
m(rand_int)=1;
old_matrix=reshape(m,[10 10]);
for i=1:10
    m=zeros(100,1);
    rand_int=datasample(1:100,1);
    m(rand_int)=1;
    new_matrix=reshape(m,[10 10]);
    if sum(abs(old_matrix-new_matrix),'All')>0
        count=count+1;
    end
    old_matrix=new_matrix
end

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Joseph Lee 2020-5-18

Yes thats exactly what I asked for thanks.

Do you know how I could modify this script so that the 1 can only move one digit from the position it is currently at per generated matrix?

Also is there a way of setting an alarm if the 1 doesn't move from its position for x number of generated matricies and resetting said alarm when its position moves?

Many thanks,

Joe

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