Distributing a cell array into another
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If I have 2 cell arrays of chars, is it possible to distribute them such that they are combined and concatenated?
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
Result = {'Category1 Mon', 'Category1 Tues', ..., 'Category1 Sun', 'Category2 Mon', 'Category2 Tues', ..., 'Category2 Sun'};
采纳的回答
Star Strider
2020-5-18
A = {'Category1 ', 'Category2 '};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
then transposing ‘A’ and adding them:
Result = string(A).' + string(B)
produces:
Result =
2×7 string array
Columns 1 through 4
"Category1 Mon" "Category1 Tues" "Category1 Wed" "Category1 Thurs"
"Category2 Mon" "Category2 Tues" "Category2 Wed" "Category2 Thurs"
Columns 5 through 7
"Category1 Fri" "Category1 Sat" "Category1 Sun"
"Category2 Fri" "Category2 Sat" "Category2 Sun"
Otherwise, the only option is likely two nested loops, concatenating elements of ‘A’ and ‘B’ in each iteration to form elements of ‘Result’.
.
更多回答（2 个）
the cyclist
2020-5-18
编辑：the cyclist
2020-5-18
Here is a straightforward way:
A = {'Category1', 'Category2'};
B = {'Mon', 'Tues', 'Wed', 'Thurs' 'Fri', 'Sat', 'Sun'};
nA = numel(A);
nB = numel(B);
Result = cell(1,nA*nB);
nc = 0;
for ia = 1:nA
for ib = 1:nB
nc = nc + 1;
Result{nc} = [A{ia},' ',B{ib}];
end
end
Fangjun Jiang
2020-5-18
0 个投票
strcat(repmat(A,size(B')),repmat({' '},[length(B),length(A)]),repmat(B',size(A)))
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