Changing matrix column order
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An having difficulty expressing the result I would like, but it is shown in the example below. How can I change the order of matrix A's columns so that they are like matrix B, regardless of the data values.
A =
1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333
B =
1 11 111 2 22 222 3 33 333
1 11 111 2 22 222 3 33 333
1 11 111 2 22 222 3 33 333
采纳的回答
Walter Roberson
2020-5-18
reshape(permute(reshape(A,size(A,1),3,[]),[1 3 2]),size(A,1),[])
3 个评论
Penny Ibil
2020-5-18
Penny Ibil
2020-5-18
Walter Roberson
2020-5-18
permute(X, [1 3 2]) means that dimension 1 should stay the same, and what was dimension 3 should become the new dimension 2, and that what was dimension 2 should become the new third dimension.
permute() is a generalization of transpose(). It moves elements around.
for I = 1 : size(A, 1)
for J = 1 : size(A,2)
for K = 1 : size(A,3);
output(I, K, J) = A(I, J, K);
end
end
end
更多回答（1 个）
Ameer Hamza
2020-5-18
编辑：Ameer Hamza
2020-5-18
For this particular example
A = ...
[1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333
1 2 3 11 22 33 111 222 333];
idx = [1 4 7 2 5 8 3 6 9];
B = A(:, idx);
Result
>> B
B =
1 11 111 2 22 222 3 33 333
1 11 111 2 22 222 3 33 333
1 11 111 2 22 222 3 33 333
1 11 111 2 22 222 3 33 333
Is there a general rule that can be expressed mathematically?
2 个评论
Penny Ibil
2020-5-18
Ameer Hamza
2020-5-18
Do you want to move all columns start with 1 to the left in increasing order, then columns of 2, then 3, so on. Something like this?
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