Info

此问题已关闭。 请重新打开它进行编辑或回答。

Avoiding for loop and if

2 次查看（过去 30 天）
Giovanni Gardan
Giovanni Gardan 2020-5-19
关闭： MATLAB Answer Bot 2021-8-20
I'd like to avoid the following "for loop". Is it possible?
In the following code, the matrix CAR_GEN is the input. This matrix has rows number=1000, and column number=4. In the first column of this matrix there are two possibilities: or 'G' or 'C', and if I have 'C' i have to do the operation under the if-test and finally find the vector ''Scarto''.
Is it possible to check directly if the element of the first column is 'C' and then do the operation in order to find 'Scarto', in order to save time?
-----------------------------------------------------------------------------------------------------------------------------
Scarto = zeros (N_nodi_tot - N_nodi_gen,1); %Array initialization
for Riga = 1:100000
if CAR_GEN(Riga,1) == abs('C')
Ncar = CAR_GEN(Riga,2);
Pcar = CAR_GEN(Riga,3)/Nbase;
Qcar = CAR_GEN(Riga,4)/Nbase;
Nload = Ntot(Riga,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);
end
end
---------------------------------------
----------------------------------------------------------------------------------------
Thanks!
  3 个评论
显示 1更早的评论
Giovanni Gardan
Giovanni Gardan 2020-5-19
Thank you very much for your answer. Is this the right way to use logical indexing?
Scarto = zeros (N_nodi_tot - N_nodi_gen,1);
cond = (CAR_GEN(:,1) == abs('C'));
Ncar = CAR_GEN(cond,2);
Pcar = CAR_GEN(cond,3)/Nbase;
Qcar = CAR_GEN(cond,4)/Nbase;
Nload = Ntot(cond,1);
Scarto(Ncar,1) = Nload - (Pcar + 1i*Qcar);

此问题已关闭。

回答（0 个）

此问题已关闭。

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by