using break to stop nested loop
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X = [1 2 3 4 5 4 3 6 7 8 9 10 11 12 11 10 9 8 7 8 9 10 9 8 7 6 5 4 3 2 1 2 4 5 6 7 8 9 11 12 11 10 9 8 7 9 10 9 8 7 6 5 4 3 2 1];
I want to take out vectors which start when value greater than 2 and end value end less than 11. The resulting vectors will be [3 4 5 4 3 6 7 8 9 10 ] and [4 5 6 7 8 9], which will be kept in cell array.
The current code I tried saved only [4 5 6 7 8 9] in fwd cell array.
Could anyone please help me to save both vectors in the cell array? thank you.
clc; clear; close all
X = [1 2 3 4 5 4 3 6 7 8 9 10 11 12 11 10 9 8 7 8 9 10 9 8 7 6 5 4 3 2 1 1 2 4 5 6 7 8 9 11 12 11 10 9 8 7 9 10 9 8 7 6 5 4 3 2 1];
start = min(X)+2;
ed = max(X) -2;
m = length(X);
f = 1;
i = 2;
while i < m
k=1;
if X(i) >= start && X(i-1) <= start && X(i+1) > X(i)
a(k) = X(i);
for j = i+1:m-1
if X(j+1) > ed && X(j+2) >= X(j+1) && X(j) < X(j+1)
b (k) = X(j);
fwd{k} = [X(i):X(j)];
if ~isempty(b(k))
break;
end
end
end
i =j+1;
k =k+1;
else
i = i+1;
end
end
3 个评论
Yu Zhi: your problem is not sufficiently defined. For example, here are two sequences that meet your requirement "start when value greater than 2 and end value end less than 11", why are they not included in the output?:
7 8 9 10
8 7 9 10
What about ther prefectly good sequence
8
which also fulfills your conditions? Why is that sequence not in your output?
HYZ
2020-5-22
Actually I am simulating a situation that an animal leaves one end and enter the other end as in the diagram.
I somehow changed the postion of k and got what I want. But honestly, I still don't really understand how putting k=1; k=k+1; can make it work.
clc; clear; close all
X = [1 2 3 4 5 4 3 6 7 8 9 10 11 12 11 10 9 8 7 8 9 10 9 8 7 6 5 4 3 2 1 1 2 4 5 6 7 8 9 11 12 11 10 9 8 7 9 10 9 8 7 6 5 4 3 2 1];
start = min(X)+10;
ed = max(X) -10;
m = length(X);
i = 2;
k=1;
while i < m
if X(i) >= start && X(i-1) <= start && X(i+1) > X(i)
a(k) = X(i);
for j = i+1:m-1
if X(j+1) > ed && X(j+2) >= X(j+1) && X(j) < X(j+1)
b (k) = X(j);
fwd{k} = [X(i):X(j)];
if ~isempty(b(k))
k=k+1;
break;
end
end
end
i =j+1;
else
i = i+1;
end
end
fwd;
HYZ
2020-5-22
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