the problem with mean function

2012 11 8
2 个回答
回答已采纳
1 次查看（30 天）

0 个投票

i use this function to build the mean of vector:
% mean_phase=mean(reshape(phase(:),25,[]))
i get this error with the size of the vector:
*Product of known dimensions, 25, not divisible into total number of elements*
How could i solve this Problem ?

请先登录，再回答此问题。

 采纳的回答

Pedro Villena
Pedro Villena 2012-11-8
编辑：Pedro Villena 2012-11-8

0 个投票

mean_phase=mean(reshape(phase(1:25*floor(numel(phase)/25)),25,[]))

更多回答（1 个）

Rica
Rica 2012-11-8

0 个投票

thanks. But my task is to have a mean value each 25 Value. I thought abaout adding some zeros at the end of the array to get the appropriate length. I do not how.

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

Andrei Bobrov
Andrei Bobrov 2012-11-8
编辑：Andrei Bobrov 2012-11-8
use Statistics Toolbox
nanmean(reshape([phase(:);nan(mod(-numel(phase),25),1)],25,[]));
or use Image Processing Toolbox
blockproc(phase(:),[25,1],@(x)mean(x.data));

请先登录，再进行评论。

类别

在 帮助中心 和 File Exchange 中查找有关 Descriptive Statistics 的更多信息

产品

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by