# keep element greater than immediate previous element

9 次查看（过去 30 天）
Hi,
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ]; I want to keep one vector whereby the next element is greater than the immediate previous element. keep = [[1 2 3 4 6 8 8.5 9 11 12 ]; to discard if the element is smaller than or equal to the immediate previous element. discard = [3 2 3 4 5 5 6] (the bold elements in x).
I am using loop to do that and I didn't get what I want. could help modify my code or advise any alternative way? thanks in advance!
clc; clear; close all
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
m = length(x);
k=1; n = 1; i =1; j=2;
while i < m-1 & j < m
if x(j) >= x(i)
keep(n) = x(j);
n=n+1;
i=i+1;
j=j+1;
elseif x(j) < x(i)
k = k+1;
i=i;
j=j+1;
end
end

### 采纳的回答

This loops does what you want:
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
m = length(x);
keep = [x(1)];
for idx=2:m
if x(idx)>keep(end)
keep = [keep,x(idx)];
else
end
end
keep
keep =
1.0000 2.0000 3.0000 4.0000 6.0000 8.0000 8.5000 9.0000 11.0000 12.0000
3 2 3 4 5 5 6
Although, depending of your goal, simply sorting the array could solve the problem in a more simplified way:
keep = unique(sort(x))
keep =
1.0000 2.0000 3.0000 4.0000 5.0000 6.0000 8.0000 8.5000 9.0000 11.0000 12.0000
##### 2 个评论显示 无隐藏 无
HYZ 2020-5-24

Can I ask another question? I am trying the way you suggested. my data are in cell arrays. X is a cell array which has a few vectors. I want to use the loop you suggested for each vector in cell array. I got an error "Operator '>' is not supported for operands of type 'cell'" ... could you suggest why > doesn't work in cell array? Thanks.
for i = 1: length(X)
keep{i}(1) = [X{i}(1)];
for idx = 2: length(X{1})
if X{i}(idx) > keep{i}(end)
keep{i} = [keep{i},X{i}(idx)];
end
end
end
In mine matlab version it works fine, it can be that older versions have some problems with double indexing in cell array. One thing you could try is to remove the variables from the cell whenever possible until you get no error anymore, ex:
x1 = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
x2 = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
X = cell(2,1);
X{1} = x1;
X{2} = x2;
keep = cell(2,1);
for i = 1: length(X)
keep{i}(1) = [X{i}(1)];
actualX = X{i};
for idx = 2:length(actualX)
actualkeep = keep{i};
actualkeep = actualkeep(end);
if actualX(idx) > actualkeep
keep{i} = [keep{i},X{i}(idx)];
end
end
end
Although I would remain with the vectorized solution I suggested if all you want is the keep array

### 更多回答（1 个）

per isakson 2020-5-24
An alternative
%%
x = [1 2 3 4 3 2 3 4 6 8 5 5 6 8.5 9 11 12 ];
%%
dx = 1;
while not( isempty( dx ) )
dx = find((diff(x)<=0));
x(dx+1)=[];
end
disp( x )
output
Columns 1 through 5
1 2 3 4 6
Columns 6 through 10
8 8.5 9 11 12
>>

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