0 个投票

I made a unit square pulse and added it to the Fourier.
The integral formula came out well, but the graph is strange.
What's the problem?(I am sorry for my poor English.)
<Code>
clear;
close all;
clc;
syms t w
y=rectangularPulse(t);
f(t)=y*exp(-i*w*t);
F=int(f(t),t,-100,100)
fplot(w,F)

请先登录，再回答此问题。

 采纳的回答

Ameer Hamza
Ameer Hamza 2020-5-24
编辑：Ameer Hamza 2020-5-25

1 个投票

This demo shows how to find the fourier and inverse fourier transforms
Fourier transform:
syms t w
y(t) = rectangularPulse(t);
F(w) = int(y(t)*exp(-1i*w*t), t, -0.5, 0.5); % pulse only exist between -0.5 to 0.5
figure;
fplot(F, [-100 100]);
Inverse:
F_inv(t) = int(F(w)*exp(-1i*w*t), w, -100, 100); % integrate frequencies between -100 to 100
t_val = linspace(-2, 2, 1000);
F_val = F_inv(t_val);
figure;
plot(t_val, F_val)

2 个评论
显示 无 隐藏 无

Jin You
Jin You 2020-5-25
thank you so much!!! It's very helpful!!!!
Ameer Hamza
Ameer Hamza 2020-5-25
I am glad to be of help!!

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by