Use of arrayfun but with passing a fixed variable to function handle?
显示 更早的评论
Hi!
I hope someone can help me with this.
The first column of my matrix contains start indices and the second stop indices that should be used to read out a segment from another vector.
From that segment some calculations are done returning a scalar, that should be stored in a third column.
This code shows the idea. WIth spikeTimes is the external vector providing the segments.
For sure it's not working, since spikeTimes is a kind of fixed variable whith another size.
matrix(:,1) = start_temp;
matrix(:,2) = stop_temp;
f = @computeS;
matrix(:,3) = arrayfun(f,start_temp,stop_temp, spikeTimes);
function thresh = computeS(a,b,spikeTimes)
thresh = max(diff(spikeTimes(a:b)));
end
And it was just an idea,I'm happy about any thoughts about a proper solution. Maybe the best is simply running a loop?
Thank you in advance, I appreciate any hints!
Eva
采纳的回答
James Tursa
2020-5-25
matrix(:,3) = arrayfun(@(a,b)max(diff(spikeTimes(a:b))),start_temp,stop_temp);
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
