Check for most occurent result in every index of a string array, how? Mean of string array.

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Clas Hagström 2020-5-25

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关闭： MATLAB Answer Bot 2021-8-20

Let's say that i have a code that returns a 3x3 string array, the strings that can occurr are A,B,C,D,E,F,G,H,I so 9 total values. Most of the time, the code returns the "right" answer, let's say that that is A,A,A,B,B,B,C,C,C but due to differences in randomly generated noise the result is sometimes off, meaning that something like A,A,G,B,B,B,C,D,C could happen. I'm thinking i could make a loop that checks the "average" string array so that if you increase the amount of times the loop is run the probability of obtaining the correct array increases as well. But i don't know what to use, the only things i've found is how to check for the most occurent value in an array and how to return that, but i want to get kind of an "average" array, how could i do it?

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Answer 1

Johannes Hougaard 2020-5-25

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I'm not completely sure I get the question, but in theory you could simply convert the char array to numbers and revert to characters

str = ['A' 'A' 'A' 'B' 'B' 'B' 'C' 'C' 'C' 'D' 'D' 'D'];
num = double(char(str(:)));
avg_str = char(mean(num)); %'B'
str = ['A' 'A' 'G' 'B' 'B' 'B' 'C' 'D' 'C' 'D' 'D' 'F'];
num = double(char(str(:)));
avg_str = char(mean(num)); %'C'

This seems to do something of what you wish.

Otherwise I'd take a look at the documentation for 'unique' that might help you.

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Johannes Hougaard 2020-5-25

在 MATLAB Online 中打开

Unfortunately your 'generate_secret_data' function was not included.

I think it could be done with the third output from unique- however 'mode' seems to be more correct.

If I've understood your data correct It'd be something like

result1 = [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "1"    "9"    NaN];
result2 = [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "C"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "1"    "9"    NaN];
result3 = [  "4"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "1"    "9"    NaN];
result4 = [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "2"    "7"    NaN];
result5 = [  "3"    "3"    "G"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "7"    "1"    "9"    NaN];
result6 = [  "3"    "3"    "A"    "2"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "3"      
    "9"    "1"    "9"    NaN];
result7 = [  "1"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "8"    "2"      
    "9"    "1"    "9"    NaN];
result8 = [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "+"    "7"    "2"      
    "9"    "1"    "9"    NaN];
result9= [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "4"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "1"    "9"    NaN];
result10 = [  "3"    "3"    "A"    "3"      
    "A"    "5"    "5"    "B"      
    "C"    "3"    "2"    "B"      
    "4"    "*"    "7"    "2"      
    "9"    "1"    "9"    NaN];

If that's the case your issue can be handled by storing the multiple results as slabs in a m-by-n-by-o three dimensional array and finding the most common entry as described below:

for ii = 1:10
    c = eval(strcat('result',num2str(ii)));
    overallresult(:,:,ii) = c;
end
clear c ii
n = size(overallresult,1);
m = size(overallresult,2);
for rowid = 1:n
    for colid = 1:m
        [slabvalue,~,slaborder] = unique(overallresult(rowid,colid,:));
        mostcommonvalue(rowid,colid) = slabvalue(mode(slaborder));
    end
end

Clas Hagström 2020-5-25

Yeah i watched some videos, you're probably right so i'll check it out.

Johannes Hougaard 2020-5-26

Agreed. The 'eval' option is hideous - It was an appaling 'quick-fix' proposed by me.

The better way to do it is to assign your output 'result' directly to the 3rd dimension of the array in a for loop. I just wasn't able to do that without writing more code than I had the time to do without having your 'generate_secret_data' function.

I'm sorry I'm not able to help you.

Check for most occurent result in every index of a string array, how? Mean of string array.

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Check for most occurent result in every index of a string array, how? Mean of string array.

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