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function or functions of a single variable

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Michel Lopes Villaluz
评论： Alejandro Peñuelas 2020-5-25
  2 个评论
Alejandro Peñuelas
Alejandro Peñuelas 2020-5-25
Hi. Please in the future write explicitly what is your question and can also use the code tool for questions instead of pasting screenshots. By doing so, we can help you efficiently.
Alejandro Peñuelas
Alejandro Peñuelas 2020-5-25
Friend, if one of the answers helped you, mark it as the accepted answer to help other users with issues like this.

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回答（3 个）

Ameer Hamza
Ameer Hamza 2020-5-25
You need to pass a function handle
fplot(@(x) -exp(-x)+x.^2+2*x+2, [0 1])
  1 个评论
Walter Roberson
Walter Roberson 2020-5-25
In current releases, character vectors are still accepted, but in future that facility will go away.
The real problem was that e is not going to be recognized as the base of the natural logarithms, so e and x would both be considered to be variables.

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Walter Roberson
Walter Roberson 2020-5-25
编辑：Walter Roberson 2020-5-25
fplot('-exp(-x)+x.^2-2*x+2',[0 1])
As far as fplot() is concerned, e is just another variable, and not the base of the natural logarithms.
Alejandro Peñuelas
The problem you are not defining the function used in fplot as an expresion with an specific variable. You also are trying to use 'e' as the 'exp()' function.
Try something like this:
% Define x as the variable of the function with @(x)
fplot( @(x) -exp(-x + x.^2 - 2*x + 2), [0, 1]);
Maybe the function is not correct but you only have to change it according to your needs.
Hope this can help you. Bye.

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