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For loop goes longer than expected.

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Dear all,
I want to extract a part of a colomn vector into another vector. I tried the following:
startSample = Fs*startTime; % Becomes 112800
stopSample = Fs*stopTime; % Becomes 152800
y5s_unfiltered = zeros(stopSample-startSample,1);
for i = startSample:stopSample
y5s_unfiltered(i,1) = y(i,1); % y is the source vector and y5s_unfiltered the destination vector
end
I would expect the for loop to go 40000 times with i in the beginning is 112800 and in the end it is 152800. But unfornately the vector y5s_unfiltered becomes a 112800x1 double vector.So it grows beyond it expected 40000x1 size.
Can you help me what is the cause for this behaviour?

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Accepted Answer

Stephen Cobeldick
Stephen Cobeldick on 29 May 2020
"Can you help me what is the cause for this behaviour?"
Because that is the indexing that you used.
You defined the loop iterator to go from 112800 to 152800, and you used those values as indices into y5s_unfiltered, so the last index of y5s_unfiltered that you allocate to will be 152800. MATLAB will simply expand that vector to suit those indices, which won't be very efficient.
The solution is to loop like this:
V = startSample:stopSample;
N = numel(V);
y5s_unfiltered = zeros(N,1);
for k = 1:N
y5s_unfiltered(k,1) = y(V(k),1);
end
Or use MATLAB's basic indexing abilities and avoid the loop entirely:
y5s_unfiltered = y(startSample:stopSample);

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Hendrik Ahuis
Hendrik Ahuis on 29 May 2020
Ummmmg yeah, you are right. I hab to add (i-startSample+1) at the destination vector. Ok Thanks

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More Answers (1)

Alan Stevens
Alan Stevens on 29 May 2020
Try
for i = 1:(stopSample-startSample+1)
y5s_unfiltered(i,1) = y(i,1); % y is the source vector and y5s_unfiltered the destination vector
end

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Hendrik Ahuis
Hendrik Ahuis on 29 May 2020
This also works. Thanks for clarification.

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