Not enough input arguments error
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Hello Guys, could anyone help me with this error? I have this code:
function [error,variance_theoritical,variance_practical,SQNR_theoritical,SQNR_practical]= quantizer(L)
x=2*9*rand(1,10000) -9;
maximum=max(x);
minimum=min(x);
delta=(maximum-minimum)/L;
range=maximum: delta: minimum;
qc=1;
error=0;
vc=1;
for k=1:1:length(range)-1;
averageOFrange=(range(k)+range(k+1))/2
k=k+1
end
avg=averageOFrange;
for i=1:1:length(x)
z=x(i);
for j=1:1:L-1
if z>=avg(j)
Level=range(j+1);
break
elseif z<avg(j)
Level=range(j);
break
Q(qc)=Level;
qc=qc+1;
end
error=error+abs(z-Q(qc));
VP(vc)= z-Q(qc);
vc=vc+1;
end
variance_theoritical=delta*delta/12;
SQNR_theoritical=9*9/variance_theoritical;
end
variance_practical=var(VP);
SQNR_practical=9*9/variance_practical;
and when I run it, this error comes out:
Error using quantizer (line 6) Not enough input arguments.
Any help? Thanks a lot in advance
1 个评论
Daniel Shub
2012-11-16
Please post the entire error message and the command you type that gives the error.
回答（1 个）
Daniel Shub
2012-11-16
The error is not in quantizer function, but rather in how you are calling it. In line 6 of whatever function you are calling is something like
x = quantizer;
without any inputs to quantizer.
6 个评论
LOLO93
2012-11-16
As Daniel pointed out, you cannot run a function that requires inputs, in this case L with out specifying it. Its giving. you an error in line 6 because it cannot find L
try calling the function like
quantizer(20) % where L=20
LOLO93
2012-11-16
LOLO93
2012-11-16
Walter Roberson
2012-11-16
Then have another routine that prompts the user for the number and then calls your quantizer routine.
LOLO93
2012-11-16
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